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10x^2-52x+64=0
a = 10; b = -52; c = +64;
Δ = b2-4ac
Δ = -522-4·10·64
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-52)-12}{2*10}=\frac{40}{20} =2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-52)+12}{2*10}=\frac{64}{20} =3+1/5 $
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